Split string to enhance the ability of J2ME's String
After from JDK1.4, String class, added the string split method to achieve the division, but the method has failed J2ME (MIDP2.0 also not to do), but the actual use of the process, sometimes we really have to used in this operation, there will be a section of code I used to achieve and share:
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backup bin conf config data eshow_sitemap.html generate.sh log maint sitemap.html svn tmp partition string theory: testing string split string, and then take the substring
backup bin conf config data eshow_sitemap.html generate.sh log maint sitemap.html svn tmp @ param original the string necessary to split
backup bin conf config data eshow_sitemap.html generate.sh log maint sitemap.html svn tmp @ paran regex string split
backup bin conf config data eshow_sitemap.html generate.sh log maint sitemap.html svn tmp @ return array of strings generated after segmentation
backup / bin / conf / data / log / maint / svn / tmp /
private static String [] split (String original, String regex)
(
/ / Get the starting position of substring
int startIndex = 0;
/ / Will result in the data first into the Vector
Vector v = new Vector ();
/ / Return the result array of strings
String [] str = null;
/ / Store the starting position when taking the substring
int index = 0;
/ / Get position of substring matching
startIndex = original.indexOf (regex);
/ / System.out.println (”0″ + startIndex);
/ / If the starting position of string is less than the length of the string, then the show did not get to the end of the string.
/ / -1 On behalf of access to the end of the
while (startIndex ( String temp = original.substring (index, startIndex); System.out.println (”" + startIndex); / / Get substring v.addElement (temp); index = startIndex + regex.length (); startIndex = original.indexOf (regex, startIndex + regex.length ()); ) v.addElement (original.substring (index + 1 - regex.length ())); / / Will convert an array of Vector objects str = new String [v.size ()]; for (int i = 0; i ( str [i] = (String) v.elementAt (i); ) / / Return the resulting array return str; )
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/ / Set to take the starting position of substring
/ / Get position of substring matching
/ / Get the end of the substring
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